计算定积分：∫10[(x-1)/(x+1)]dx

计算定积分：∫¹₀[(x-1)/(x+1)]dx
【正确答案】：∫¹₀[(x-1)/(x+1)]dx=∫¹₀{[(x+1)-2]/(x+1)}dx=∫¹₀[1-2/(x+1)]dx=[x-2ln(x+1)]¹₀=1-2ln2．

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